55x^2+490x-45=0

Solution for 55x^2+490x-45=0 equation:

55x^2+490x-45=0

a = 55; b = 490; c = -45;
Δ = b2-4ac
Δ = 4902-4·55·(-45)
Δ = 250000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{250000}=500$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(490)-500}{2*55}=\frac{-990}{110}
=-9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(490)+500}{2*55}=\frac{10}{110}
=1/11
$